
Bradford T. answered 03/06/23
Retired Engineer / Upper level math instructor
y = -0.345x+19.886
y= -0.013x+13.884
Subtract the two equations
0=-0.332x+6.002
x = 6.002/0.332≈18.08
y = -0.345(18.08)+19.886 ≈13.65%
LUCENT B.
asked 03/06/23The pattern of higher rates of current alcohol use, binge alcohol use, and heavy alcohol use among full-time college students than among others aged 18 to 22 has remained consistent since 2002. Using data from 2002 to 2008, the equations representing the percents of young adults aged 18 to 22 who used alcohol are shown below, where x represents the number of years after 2000. Enrolled in college y=-0.345x+19.886 Not enrolled y=-0.013x+13.884.Percent for those enrolled in college will equal that for those not enrolled. What will the percent be?
Bradford T. answered 03/06/23
Retired Engineer / Upper level math instructor
y = -0.345x+19.886
y= -0.013x+13.884
Subtract the two equations
0=-0.332x+6.002
x = 6.002/0.332≈18.08
y = -0.345(18.08)+19.886 ≈13.65%
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