
Stanton D. answered 03/06/23
Tutor to Pique Your Sciences Interest
Hi Suyong P.,
Did you draw a sketch of the trough, in cross-section? That should convince you that when the water is 30 cm deep out of 50 cm trough height, the waterline width is 60% of the change from 30 cm to 80 cm -- in short, 60 cm. You are thus filling an area of (60 cm x 10 m) at a rate of 0.2 m^3 min^(-1). Suggest division is the operation you need? Always carry your dimensional units over through a calculation, to make sure that you did the right calculation!
-- Cheers, --Mr. d.
P.S. Hope you don't come up dry on this one, that would suggest a misreading of the problem ....

Anthony T.
The question is asking for the instantaneous rate of change of volume at 30 cm. This would involve finding the derivative of a volume vs. time function. You would need to find a formula for volume vs. height, then take the derivative of volume vs. time and solve for dh/dt.03/08/23