Raymond B. answered 03/04/23
Math, microeconomics or criminal justice
c=25/4
f(x) = sqrx - x/5
f(a) = sqr0 -0/5 = 0
f(b) = sqr25 - 25/5 = 5-5=0
f(a)=f(b) is the extra requirement for Rolle's Theorem
0=0
f'(c) = 1/2sqrc - 1/5 = (f(b)-f(a))/(b-a) = 0/25 = 0
1/2sqrc = 1/5
2sqrc = 5
sqrc = 5/2
c = (5/2)^2 = 25/4
the other two requirements for Rolle's Theorem are the requirements for the Mean Vallue Theorem
that f(x) is continuous on the closed interval [0,25] and differentiable on the open interval (0,25)
Rolles is a special case of the MVT
f'(25/4)= 1/2sqr(25/4) -1/5 = 1/5-1/5 = 0

Roger R.
03/04/23