Raymond B. answered 03/04/23
Math, microeconomics or criminal justice
f(a)= f(2)=1-48+16 = -21
f(b)=f(4)=1-96+64= -21
f(a)=f(b)
f(x) = 1-24x +4x^2
f'(x) =-24 +8x
f'(c) = -24 + 8c = 0
8c = 24
c = 3
f(x) is an upward opening parabola which is continuous and differentiable everywhere, including the interval [2,4]
f'(c)=f(3)=-24+8(3)=0
slope of the secant line from (2,-21) to (4,-21) = 0
the slope of f'(c) = f'(3) = 0 = the slope of the tangent line at (3,-35)= vertex =minimum point of the parabola