Yefim S. answered 03/03/23
Math Tutor with Experience
If(1/4)- P3(1/4)I < 1/5000;
So, -1/5000 + P3(1/4) < f(1/4) < 1/5000 + P3(1/4);
P3(1/4) = - 85/384
-1/5000 - 85/384 < f(1/4) < 1/5000 - 85/384;
-0.2216 < f(1/4) < - 0.2212
Ellie C.
asked 03/03/23I am struggling with the attached question. I would really appreciate an explanation -- thank you!
The Taylor polynomial
about x = 0 is used to approximate the value of the function f at
Find the value that verifies 
Choices:

Yefim S. answered 03/03/23
Math Tutor with Experience
If(1/4)- P3(1/4)I < 1/5000;
So, -1/5000 + P3(1/4) < f(1/4) < 1/5000 + P3(1/4);
P3(1/4) = - 85/384
-1/5000 - 85/384 < f(1/4) < 1/5000 - 85/384;
-0.2216 < f(1/4) < - 0.2212
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Ellie C.
Thank you! I understand that part, but how would I find one of the answer choices from there? Thank you so much for your help once again.03/03/23