
Yefim S. answered 03/02/23
Math Tutor with Experience
a) Cross section area A(x) = (6 - 2√x)2 and volume v = ∫09(6 - 2√x)2dx = (36x - 24 ·2/3x3/2 + 2x2)09 = 54
b) Cross section area A(y) = π(y2/4)2/8 = πy4/128; volume v = ∫06πy4/128dy = πy5/64006 = 243π/20 = 38.17