The tangent line equation is y-f(2) = f'(2)(x+2)
f'(x) = -4/x2 so f(-2) = -2 and f'(2) = -1
y+2 = -(x+2) or y = -x - 4
The normal line will be the line perpendicular to the tangent: slope of 1 through the point (-2,-2)
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