Inactive Tutor answered 20d
The vectors are linearly independent when their determinant is not zero: =6k+7−k^2
Set it equal to zero to find when they are not independent:
6k+7−k^2=0
k^2−6k−7=0
(k−7)(k+1)=0
So:
k=−1ork=7
Therefore,
a=−1,b=7
and the vectors are linearly independent precisely when:
k≠−1