a - 3b + c = 1
2a - 4b - c = 1
3a - 5b - 3c = 1
Multiply the first equation by -2 and add to the second and multiply the first equation by -3 and add to the third:
a - 3b + c = 1
2b - 3c = -1
4b - 6c = -2
Multiply the second equation by -2 and add to the third:
a - 3b + c = 1
2b - 3c = -1
0 = 0
From the second equation, b = (3c - 1) / 2 = (3/2)c - (1/2)
So, a - 3[(3/2)c - (1/2)] + c = 1.
a = (7/2)c - (1/2)
a = (7/2)c - (1/2)
b = (3/2)c - (1/2)
c = any real number (or c = c)
