Raymond B. answered 02/19/23
Tutor
5
(2)
Math, microeconomics or criminal justice
f'(x) = [ln(lnx)]'
= (1/lnx)(lnx)'
= (1/lnx)(1/x)
= 1/xlnx
f'(6) = 1/6ln6
= about but ever slightly less than 0.09302
rounded off to 5 decimal places