
Bradford T. answered 02/16/23
Retired Engineer / Upper level math instructor
r1+r2=200
r2 = 200-r1
20r1+15r2=3475
20r1+15(200-r1)=3475
20r1+3000-15r1=3475
5r1=475
r1=95
r2=200-95=105

Bradford T.
Each of the 2 rates.02/17/23
Jamo M.
asked 02/16/23Two mechanics worked on a car. The first mechanic worked for 20 hours, and the second mechanic worked for 15 hours. Together they charged a total of 3475. What was the rate charged per hour by each mechanic if the sum of the two rates was 200 per hour?
Bradford T. answered 02/16/23
Retired Engineer / Upper level math instructor
r1+r2=200
r2 = 200-r1
20r1+15r2=3475
20r1+15(200-r1)=3475
20r1+3000-15r1=3475
5r1=475
r1=95
r2=200-95=105
Bradford T.
Each of the 2 rates.02/17/23
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Jamo M.
sorry to ask but what do the r's stand for?02/16/23