Kai M.

asked • 02/16/23

Find the distance, in feet, a particle travels in its first 2 seconds of travel, if it moves according to the velocity equation v(t)= 6t2 − 18t + 12 (in feet/sec).

Find the distance, in feet, a particle travels in its first 2 seconds of travel, if it moves according to the velocity equation v(t)= 6t2 − 18t + 12 (in feet/sec).

 4 

5 

6

 −1

1 Expert Answer

By:

Richard C. answered • 02/16/23

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