Bfsfsf G.

asked • 02/15/23

Help confidence interval

A sample of size n= 99  is drawn from a population whose standard deviation is =σ 38. Find the margin of error for a 95% confidence interval for μ. Round the answer to at least three decimal places.

Robert B.

tutor
For a 95% confidence interval, the critical value of z, z_α/2, would be 2.58, so with that the margin of error will be E = z_α/2 * σ/sqrt(n) = 2.58 * 38/sqrt(99) = 9.85, and if you have any questions let me know. Hope that helps!
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02/22/23

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