
Yefim S. answered 02/16/23
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Let x = 0 at 1990; then at 1998 x = 8
C(x) = ax + b; C(0) = b = 104; C(8) = 8a + b = 224; 8a = 224 - 104; a = 120/8 = 15
C(x) = 15x + 104