P(1 or more) = 1 - P(0)
For any case with n tries: P(1 or more) = 1 - (1-p)n
In 10 tries: P(1 or more) = 1 - (.2)10
You can work out the rest.
Please consider a tutor. Take care.
Brandon W.
asked 02/15/23If one event has an 80% of occuring. Whats the probability of that event occuring if repeated 2,5,10 times. In other words if 5 events all with 80% probability of occuring ran simultaneously what is the probability of one or more occuring?
P(1 or more) = 1 - P(0)
For any case with n tries: P(1 or more) = 1 - (1-p)n
In 10 tries: P(1 or more) = 1 - (.2)10
You can work out the rest.
Please consider a tutor. Take care.
Replace the p=0.01 with your p=0.8 in the solved question below.
https://www.quora.com/How-would-one-calculate-the-probability-of-the-occurrence-of-an-event-over-multiple-attempts-1-chance-over-10-tries
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