
William W. answered 02/14/23
Experienced Tutor and Retired Engineer
As a reminder, the derivative rule for an exponential goes like this:
When you to evaluate ∫23x, you are asking, "What expression, when we take it's derivative, gives us 23x?
Let's first try 23x. Take its derivative using the rule above PLUS the chain rule and we get:
ln(2)•23x•(3) or 3ln(2)•23x which is close, but it has that extra "3ln(2)" on it. Can you see that if we use 23x/(3ln(2)) that the denominator would cancel out that extra term we got, and we would be left with just 23x (which is what we want)? Of course, we would need to add "+ C" to cover any constant term.