
William W. answered 02/14/23
Experienced Tutor and Retired Engineer
the limit definition of a derivative is:
f(x + h) = 5(x + h)2 + 2(x + h) + 4 = 5(x2 + 2xh + h2) + 2x + 2h + 4 = 5x2 + 10xh + 5h2 + 2x + 2h + 4
So:
f(x + h) - f(x) = 5x2 + 10xh + 5h2 + 2x + 2h + 4 - (5x2 + 2x + 4)
f(x + h) - f(x) = 5x2 + 10xh + 5h2 + 2x + 2h + 4 - 5x2 - 2x - 4
f(x + h) - f(x) = 10xh + 5h2 + 2h = h(10x + 5h + 2)
And (f(x + h) - f(x))/h = h(10x + 5h + 2)/h = 10x + 5h + 2
So the limit of this as h approaches zero is 10x + 2
So f '(x) = 10x + 2
meaning f '(2) = 10(2) + 2 = 22