Yefim S. answered 02/08/23
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y3 - y2 = 2y; y = 0, y = -1, y = 2
- Area A = ∫-10(y3 - y2 - 2y)dy + ∫02(2y + y2 - y3)dy = (y4/4 - y3/3 - y2)-10 + (y2 + y3/3 - y4/4)02 = - 1/4 - 1/3 + 1 + 4 + 8/3 - 4 = 37/12