
Yefim S. answered 02/05/23
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4 - x2 = 0; x = 2. By Shells Method V = 2π∫02x(4 - x2)dx = 2π(2x2 - x4/4)02 = 2π(8 - 4) = 8π
x = √(4 - y); 0 ≤ y ≤ 4; By Disk methodV = π∫04(4 - y)dy = π(4y - y2/2)04 = π(16 - 8) = 8π