
Yefim S. answered 02/05/23
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By Shells Method V = 2π∫23x(x4- 16)dx = 2π(x6/6 - 8x2)23 = 2π[(243/2 - 72) - (32/3 - 32)] = 425/3π
Hanas J.
asked 02/05/23Yefim S. answered 02/05/23
Math Tutor with Experience
By Shells Method V = 2π∫23x(x4- 16)dx = 2π(x6/6 - 8x2)23 = 2π[(243/2 - 72) - (32/3 - 32)] = 425/3π
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