Maria L.

asked • 02/03/23

cross area calculus

for the function; 𝑦=2sec(𝑥).

Identify the correct description of the cross section perpendicular to the 𝑥-axis located at 𝑥.

a)The cross section at location 𝑥 is a circle of radius 𝑅=2.

b)The cross section at location 𝑥 is a circle of radius 𝑅=2sec(𝑥).

c)The cross section at location 𝑥 is a circle of radius 𝑅=2sec(𝑥)−2.

d)The cross section at location 𝑥 is a circle of radius 𝑅=sec(𝑥).


1 Expert Answer

By:

David S. answered • 03/11/23

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