Adam S.

asked • 02/02/23

Solve the initial-value problem for y as a function of x.

  1.  (16-x^2)dy/dx = 1, y(0) = 2
  2. (x^2 + 64) dy/dx = 1, y(8) = 0

Paul M.

tutor
Both of these problems are really simple integration problems via direct trig substitution. Do you have a specific question...something you don't understand?
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02/02/23

Adam S.

Hi, I am just a bit confused by the wording of the problem and how I am supposed to set up the integral, could you help me with that?
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02/02/23

1 Expert Answer

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Doug C. answered • 02/02/23

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