
Bradford T. answered 02/01/23
Tutor
4.9
(29)
Retired Engineer / Upper level math instructor
m = (y2-y1)/(x2-x1) = (1- -19)/(r-6)=20/(r-6) = 5
20 = 5(r-6) = 5r-30
5r=50
r=10

Michael D.
asked 02/01/23Bradford T. answered 02/01/23
Retired Engineer / Upper level math instructor
m = (y2-y1)/(x2-x1) = (1- -19)/(r-6)=20/(r-6) = 5
20 = 5(r-6) = 5r-30
5r=50
r=10
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Luke J.
(x1, y1) = (6, -19) and (x2, y2) = (r, 1). y2-y1 = 1 - (-19) = 20, x2-x1 = r - 6. I suggest a re-work of your solution.02/03/23