what is the point slope form of: passing through (9,-4) and perpenicular to the line whose equation is x-9y-7=0?

Question

what is the point slope form and general form

Answer 1

Equation of line given

 

x-9y-7=0

 

slope intercept form of equation is

 

9y=x-7

 

y=1/9 x -7/9

 

 

so slope of line perpendicular this line is = -9

 

point slope form of equation is

 

y-y1=m(x-x1)

 

y-(-4)=-9(x-9)

y+4=-9(x-9) ...............point slope form

 

general form of equation is

 

y+4=-9x+81

 

simplifying

 

-9x-y-77=0 ------------general form