Mark M. answered 01/25/23
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
y' = 2cosx
Slope = 2cos(π/6) = 2(√3/2) = √3
Equation of tangent line: y - 1 = √3 (x - π/6)
y = (√3)x + (1 - √3(π/6))
Baba B.
asked 01/25/23Find the equation of the tangent line to the curve y = 2sin x at the point (pi/6,1).
The equation of this tangent line can be written in the form y = mx + b where,
m =
b =
Mark M. answered 01/25/23
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
y' = 2cosx
Slope = 2cos(π/6) = 2(√3/2) = √3
Equation of tangent line: y - 1 = √3 (x - π/6)
y = (√3)x + (1 - √3(π/6))
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