P(at least 2 blue balls) = P(exactly 2 blue balls) + P(exactly 3 blue balls) = C(3,2)(1/3)2(2/3) + (1/3)3 = 7/27
Hope this helps!
Cameron L.
asked 01/12/23P(at least 2 blue balls) = P(exactly 2 blue balls) + P(exactly 3 blue balls) = C(3,2)(1/3)2(2/3) + (1/3)3 = 7/27
Hope this helps!
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.