The volume of the inverted pyramid is (1/3)x2y where x(t) is the side of the square and y(t) is the height of the pyramid at the water level. (Hence, it is the volume of water added by time t.
We want to express x as x(y) so that V can be V(y). The ratio of x to y will always be 7/10 because of similarity.
V = (1/3)(7y/10)2y = (49/300)y3
dV/dt = (49/100)y2(dy/dt) and dy/dt = (100/49)(dV/dt)/(3 cm)2 = 14.74 cm/s with dV/dt=65 cm3/s
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