Edward C. answered 03/23/15
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Let X = liters of 65 octane gasoline
Let Y = liters of 78 octane gasoline
13 liters ==> X + Y = 13 ==> Y = 13 - X
To get 13 liters of 75 octane gasoline will require X liters of 65 octane gasoline and (13 - X) liters of 78 octane gasoline to add up to 13 * 75
65*X + (13 - X)*78 = 75 * 13
65*X + 1014 - 78*X = 975
-13*X = -39
X = 3
So Y = 13 - 3 = 10
There should be 3 liters of 65 octane gasoline and 10 liters of 78 octane gasoline
Check: 3*65 + 10*78 = 195 + 780 = 975, and 975/13 = 75