v(t)=2 + ∫a(x) dx from 0 to t....=2 + (32/5) sin 5t
s(t) = 4 +∫v(x) dx from 0 to t....I'll leave this step for you to finish.
Henry Z.
asked 12/16/22Given the acceleration, initial velocity, and initial position of a body moving along a coordinate line at time t, find the body's position at time t.
a=32cos 5t, v(0)=2, s(0)=4
v(t)=2 + ∫a(x) dx from 0 to t....=2 + (32/5) sin 5t
s(t) = 4 +∫v(x) dx from 0 to t....I'll leave this step for you to finish.
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