Find the absolute maximum and minimum values of f(t)=2cost+sin2t on the interval [0,π/2]

Answer 1

Graph this equation first.

f'(t)=-2 sin x+2 cos 2x=0

Substitute: -sin x+(sin²x-1)=0

^{Solve for sin x to and find sin x =1/2...which gives values for the minimum points of π/2 and 5π/2}