dA/dt = 2s ds/dt
Plug in the values from the problem and solve for ds/dt.
Femi ..
asked 12/10/22The area of a square is increasing at a rate of 30 centimeters squared per second. Find the rate of change of the side of the square when it is 5 centimeters.
The rate of change of the side is=
dA/dt = 2s ds/dt
Plug in the values from the problem and solve for ds/dt.
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