Find the equation of the linear function that has a slope of -8/3 and passes through the point (-3,4)

Answer 1

The point-slope form of a line is:

y - y₁ = m(x - x₁) where "m" is the slope of the line and (x₁, y₁) is a point on the line. In your case m = -8/3 and x₁ = -3 and y₁ = 4. Plug these into the equation:

y - 4 = (-8/3)(x + 3)