Inactive Tutor answered 02/17/24
1.7(36) =61.2 tons for 36 cars and mean 1.7 tons, standard deviation = 1/2 ton
find z score for 66 tons
z = (66-61.2)/.5(36)
4.8/.5(36) = .2666... = z, .395 = 39.5% chance of exceeding 66 tons
Blessing B.
asked 12/06/22A ferry will safely accommodate 66 tons of passenger cars. Assume that the mean weight of a passenger car is 1.7 tons with standard deviation 0.5 tons. If a random sample of 36 cars are loaded onto the ferry, what is the probability that the maximum safe weight will be exceeded? Hint! Think about the average safe weight.
Inactive Tutor answered 02/17/24
1.7(36) =61.2 tons for 36 cars and mean 1.7 tons, standard deviation = 1/2 ton
find z score for 66 tons
z = (66-61.2)/.5(36)
4.8/.5(36) = .2666... = z, .395 = 39.5% chance of exceeding 66 tons
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