θ=π is just the y axis in Cartesian co=ordinates.
The area in question is the interior of a semi-circle.
What does 1.5π have to do with it?
Paul M.
tutor
OK, so you mean 3/4 of a circle, including what are usually called quadrants 1, 2 and 3. BUT your description is equivocal, which is why I was confused by your statement.
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12/06/22
Haley L.
1.5π is the upper bound of theta12/06/22