
Aime F. answered 12/05/22
Experienced University Professor of Mathematics & Data Science
Rn = ∑j=1nf(xj)Δx
= ∑j=1nf((j–1)Δx)Δx
= ∑j=1nf((j–1)/(n–1))/(n–1)
= ∑j=2n(j–1)3/(n–1)4
= ∑k=1n–1k3/(n–1)4
= (n–1)2n2/4(n–1)4
= (n/(n–1))2/4
→n→∞ 1/4.
Sue-Tanya B.
asked 12/05/221.The area A of a region that lies under the graph of the continuous function f is given by A = limn→∞ Rn = limn→∞ [f(x1)∆x + f(x2)∆x + · · · + f(xn)∆x].
(a) Use this definition to find an expression for the area under the curve y = x^3 from 0 to 1 as a limit.
Aime F. answered 12/05/22
Experienced University Professor of Mathematics & Data Science
Rn = ∑j=1nf(xj)Δx
= ∑j=1nf((j–1)Δx)Δx
= ∑j=1nf((j–1)/(n–1))/(n–1)
= ∑j=2n(j–1)3/(n–1)4
= ∑k=1n–1k3/(n–1)4
= (n–1)2n2/4(n–1)4
= (n/(n–1))2/4
→n→∞ 1/4.
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