The limit limh→0cos(0.5⋅π+h)/h is the derivative of some function f(x) evaluated at x=a

Question

The limit limh→0cos(0.5⋅π+h)/h is the derivative of some function f(x)f(x) evaluated at x=a

Answer 1

Since cos(π/2) = 0, the given limit is equivalent to lim_h→0 [(cos(π/2+h) - cos(π/2)) / h], which is the derivative of cosx evaluated at π/2. So, the value of the limit is -1.