Dayv O. answered 11/29/22
Caring Super Enthusiastic Knowledgeable Calculus Tutor
The calculations below are not left point or rjght point sums but very close to mid point if the velocity is a linear function of time between seconds. The interval 4s. to 5s. creates a special problem. Notice acceleration is changing at integer t moments abruptly (dv/dt), but velocity is continuous at those points. I drew lines creating triangles plus boxes for area calculation. Then for sure acceleration is discontinuous at those points.
If the idea is only to use boxes for area for the left and right sums, then adding up shaded boxes
might be the simple way of answering without estimating any closer.
the right point box areas add to -2. the left point box areas add to -9 in movement sum.
For displacement, right box add without regard to direction to 20. Displacement left box method =21.
I calculated movement equaled -5.75 in sum. Without regard to direction displacement =20.5
remember to include both box area and triangle areas for each second.
For time 4s. to 5s. it is a bit tricky. There is negative area from 4s. to 4.75s.
and positive area from 4.75s. to 5s.. The triangle of both with base 4s. to 5s.
is 4 high so has area 2 (area is movement in units and in calculus). Positive area
is (1/2)*.25*1=.125 so negative area is 2-.125
To find where x is when the triangle hypotenuse crosses x-axis, must
use slope=4=(y+3)/(x-4),,,and set y=0

