How do I find if this series converges or diverges?

Question

From n = 1 to infinity, Σ (-1)ⁿ(1 - 1/n)^{n^2}, does the series converge absolutely or diverge?

Answer 1

This series should look somewhat familiar.

It is an alternating term series in which the terms absolutely decrease; therefore, it converges by Leibnitz's Theorem.

Each term of the series is absolutely less than [(1-(1/n)]ⁿ which converges to e; . it converges absolutely