Use the given theorem to evaluate the definite integral.

Question

0	(8x2 + 8x) dx
−2

 I got 58/3 but its telling me that is wrong Im not sure where I messed up

Answer 1

_-2∫⁰ 8x² + 8x dx = [(8/3)x³ + 4x²] evaluated between -2 and zero =

[(8/3)(0)³ + 4(0)²] - [(8/3)(-2)³ + 4(-2)²]

= [0] - [(-64/3) + 16]

= 0 - [(-64/3) + (48/3)]

= 0 - (-16/3)

= 0 + 16/3

= 16/3