Your hypothesis says that the antiderivative of f(x)+1 is a constant; therefore, f(x)+1=0 and f(x)=-1.
Fryal N.
asked 11/17/22If ∫(8f(x) + 8) dx = 2, then ∫f(x)dx=
If ∫(8f(x) + 8) dx = 2, then ∫f(x)dx=
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