Yefim S. answered 11/11/22
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{f(x) = (x + 2)2/2 + C1 for x ≤ - 1, f(x) = x3/3 + C2 for x ≥ -1} only at x = - 1 we have to have equal values. So, 1/2 + C1 = -1/3 + C2; C2 = C1 + 5/6. {f(x) = (x + 2)2/2 + C1 for x ≤ - 1, f(x) = x3/3 + C1 + 5/6 for x ≥ -1}