Yefim S. answered 11/09/22
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3(7x - y2)2(7 - 2yy') = 6; 2/(7x - y2)2 = 7 - 2yy'; y' = 7/(2y) - 1/[y(7x - y2)2]
Maria L.
asked 11/09/22Find the y' using implicit differentiation (7𝑥−𝑦^2)^3=6𝑥
Yefim S. answered 11/09/22
Math Tutor with Experience
3(7x - y2)2(7 - 2yy') = 6; 2/(7x - y2)2 = 7 - 2yy'; y' = 7/(2y) - 1/[y(7x - y2)2]
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