Need help solving

Question

Use a right triangle to write the given expression as an algebraic equation. Assume that X is positive and that the given inverse trigonometric function is defined with the expression in X.

sec(sin^-1(x/sqrt (x²+4)))

Answer 1

[sqr(x^2+4)]/2 = sec(sin^-1(x/sqr(x^2+4))x

sinT = x/sqr(x^2+4)

cosT= 2/sqr(x^2+4)

secT= 1/cosx = sqr(x^2+4)/2

the right triangle has hypotenuse= sqr(x^2+4)

opposite side = x

and adjacent side = 2

secT =1/cosT = hypotenuse/adjacent = sqr(x+4)/2