Bradford T. answered 11/04/22
Retired Engineer / Upper level math instructor
a) y = f(x) = x1/3
b) dy = dx/(3x2/3)
c) 220 is close to 63, so x = 216
d) dx = 220-216 = 4
e) dy = 4/(3(6)2) = 4/108 ≈ 0.0370
Note: y ≈ 2161/3 + dx = 6.0370
The actual value of 2201/3 ≈ 6.03681
(6.03681-6.037)/6.03681 ≈-0.0000265 = -0.00265% error. Not too bad.
220