You need the derivatives of x2sinx to f''':
f' = 2xsinx + x2cosx
f'' = 2sinx + x sinx + 2xcosx +2xcosx - x2sinx = (2-x2)sinx +4xcosx
f''' = (2-x2)cosx - 2xsinx +4cosx -4xsinx = (6-x2)cosx -6xsinx (checked)
The c3 term is f'''(0)/3!
Please consider a tutor. Take care.