Inactive Tutor answered 10/31/22
Area = 1250 = xy --> y = 1250/x
Cost = 2(4)y + 4x + 12x = 8y +16x = 8(1250)/x + 16x
C'(x)= -8(1250)/x2 + 16
Set C'(x) to zero and solve for x
16x2 = 8(1250)
x2 = 625
x = 25 feet
y = 1250/25 = 50 feet
Monkey D L.
asked 10/31/22If the area of the garden is 1250 ft2, find the dimensions of the garden minimizing the cost. (Let x be the length of the brick wall and y be the length of an adjacent side in feet.)
Inactive Tutor answered 10/31/22
Area = 1250 = xy --> y = 1250/x
Cost = 2(4)y + 4x + 12x = 8y +16x = 8(1250)/x + 16x
C'(x)= -8(1250)/x2 + 16
Set C'(x) to zero and solve for x
16x2 = 8(1250)
x2 = 625
x = 25 feet
y = 1250/25 = 50 feet
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