Let x = rate of the faster bus. Then x - 9 = rate of the slower bus
Distance = (rate)(time)
They meet when distance of faster bus + distance of slower bus = 1841
So, 7x + 7(x - 9) = 1841
Solve for x.
Patrick P.
asked 10/27/22Two buses leave towns 1841
kilometers apart at the same time and travel toward each other. One bus travels 9
kmh
slower than the other. If they meet in 7
hours, what is the rate of each bus?
Let x = rate of the faster bus. Then x - 9 = rate of the slower bus
Distance = (rate)(time)
They meet when distance of faster bus + distance of slower bus = 1841
So, 7x + 7(x - 9) = 1841
Solve for x.
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