Mark M. answered 10/24/22
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
dy/dx = sin y / x
d2y / dx2 = [x(cosy)(dy/dx) - siny] / x2 = [x(cosy)(siny / x) - siny] / x2 = [(cosy)(siny) - siny] / x2
= siny (cosy - 1) / x2