Please help with my homework

Question

write the solution as a compound inequality( + 8) (x +1) > 0

Answer 1

(+8)(x+1) >0

8x+8 >0

x+1 >0

x >-1

That's assuming that ( +8)(x+1)>0 didn't leave out another variable in the space between the 1st parenthesis and +8. It's an odd way to write 8, as + is implied if it's alone. If there was an x before the +8 then

(x+1)(x+1)>0

x+1>0

x>-1 is one solution, taking the square root of both sides

also

-(x+1)>0 by taking the negative square root of both sides

x+1<0 as the inequality reverses direction when multiplied by a negative number

x <-1 is a 2nd solution

putting them together the full solution is

x = any real number except -1

in interval notation (-infinity,-1)U(-1, infinity)

or maybe you left out a 2nd y before ( +8)??

inequality( +8)(x+1)>0 is odd in running together the "y" of inequality right next to the 1st parenthesis

If you meant the

inequality y( +8)(x+1)>0

or maybe

(y+8)(x+1)>0

it has different solutions

Answer 2

Solve to find x> -1