I want to achieve 24 more wins than losses and I win 60% of the time, what is the fewest amount of games I need to play?

Question

I want to achieve 24 more wins than losses and I win 60% of the time, what is the fewest amount of games I need to play?

Answer 1

Total games x 60% wins = total wins (x)

Then total games = x/0.6

similarly total games x 40% losses = total losses (y)

Then total games = y/0.4

Hence x/0.6 = y/0.4, etc.

Answer 2

I would suggest starting off with defining the number of wins as x and number of losses as y. Writing the equations down, you will x-y=24 (Since the difference between wins and losses should be 24). The second equation will have 40/100 x= 60/100 y (using percentage ratio x/60%=y/40%)